Base | Representation |
---|---|
bin | 1100000001001010110011… |
… | …1101100111000010101111 |
3 | 1201210021012210112202211021 |
4 | 3000102230331213002233 |
5 | 3213000211113444401 |
6 | 44034310205035011 |
7 | 2532460502141134 |
oct | 300225475470257 |
9 | 51707183482737 |
10 | 13214221234351 |
11 | 4235135435835 |
12 | 1595007b55a67 |
13 | 74b132396957 |
14 | 339800b2c58b |
15 | 17daeb3902a1 |
hex | c04acf670af |
13214221234351 has 2 divisors, whose sum is σ = 13214221234352. Its totient is φ = 13214221234350.
The previous prime is 13214221234283. The next prime is 13214221234369. The reversal of 13214221234351 is 15343212241231.
13214221234351 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13214221234351 - 221 = 13214219137199 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13214221244351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6607110617175 + 6607110617176.
It is an arithmetic number, because the mean of its divisors is an integer number (6607110617176).
Almost surely, 213214221234351 is an apocalyptic number.
13214221234351 is a deficient number, since it is larger than the sum of its proper divisors (1).
13214221234351 is an equidigital number, since it uses as much as digits as its factorization.
13214221234351 is an evil number, because the sum of its binary digits is even.
The product of its digits is 34560, while the sum is 34.
Adding to 13214221234351 its reverse (15343212241231), we get a palindrome (28557433475582).
The spelling of 13214221234351 in words is "thirteen trillion, two hundred fourteen billion, two hundred twenty-one million, two hundred thirty-four thousand, three hundred fifty-one".
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