Base | Representation |
---|---|
bin | 11110000010111011001110… |
… | …010000011011001111101011 |
3 | 122022212200200202012020010122 |
4 | 132002323032100123033223 |
5 | 114310010141101204011 |
6 | 1145013220332433455 |
7 | 36555655313244323 |
oct | 3602731620331753 |
9 | 568780622166118 |
10 | 132142424241131 |
11 | 391173185a1417 |
12 | 129a210661888b |
13 | 5896c91a03b45 |
14 | 248ba2820a283 |
15 | 10424db00b3db |
hex | 782ece41b3eb |
132142424241131 has 2 divisors, whose sum is σ = 132142424241132. Its totient is φ = 132142424241130.
The previous prime is 132142424241103. The next prime is 132142424241161. The reversal of 132142424241131 is 131142424241231.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 132142424241131 - 210 = 132142424240107 is a prime.
It is a super-2 number, since 2×1321424242411312 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 132142424241091 and 132142424241100.
It is not a weakly prime, because it can be changed into another prime (132142424241161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66071212120565 + 66071212120566.
It is an arithmetic number, because the mean of its divisors is an integer number (66071212120566).
Almost surely, 2132142424241131 is an apocalyptic number.
132142424241131 is a deficient number, since it is larger than the sum of its proper divisors (1).
132142424241131 is an equidigital number, since it uses as much as digits as its factorization.
132142424241131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 36864, while the sum is 35.
Adding to 132142424241131 its reverse (131142424241231), we get a palindrome (263284848482362).
The spelling of 132142424241131 in words is "one hundred thirty-two trillion, one hundred forty-two billion, four hundred twenty-four million, two hundred forty-one thousand, one hundred thirty-one".
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