Base | Representation |
---|---|
bin | 10011001110101011010… |
… | …111110101010010111110 |
3 | 11200022211201212220112121 |
4 | 103032223113311102332 |
5 | 133122242102031142 |
6 | 2451020121153154 |
7 | 164320161422341 |
oct | 23165327652276 |
9 | 4608751786477 |
10 | 1321430111422 |
11 | 46a462937083 |
12 | 19412832b7ba |
13 | 977c1b64445 |
14 | 47d59780458 |
15 | 245904d2c67 |
hex | 133ab5f54be |
1321430111422 has 4 divisors (see below), whose sum is σ = 1982145167136. Its totient is φ = 660715055710.
The previous prime is 1321430111363. The next prime is 1321430111467. The reversal of 1321430111422 is 2241110341231.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 330357527854 + ... + 330357527857.
It is an arithmetic number, because the mean of its divisors is an integer number (495536291784).
Almost surely, 21321430111422 is an apocalyptic number.
1321430111422 is a deficient number, since it is larger than the sum of its proper divisors (660715055714).
1321430111422 is an equidigital number, since it uses as much as digits as its factorization.
1321430111422 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 660715055713.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 1321430111422 its reverse (2241110341231), we get a palindrome (3562540452653).
The spelling of 1321430111422 in words is "one trillion, three hundred twenty-one billion, four hundred thirty million, one hundred eleven thousand, four hundred twenty-two".
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