Base | Representation |
---|---|
bin | 10011001110101011011… |
… | …111100010100111001011 |
3 | 11200022211212200120022102 |
4 | 103032223133202213023 |
5 | 133122243111211133 |
6 | 2451020232344015 |
7 | 164320214536352 |
oct | 23165337424713 |
9 | 4608755616272 |
10 | 1321432132043 |
11 | 46a463a97211 |
12 | 194128b4500b |
13 | 977c23c108a |
14 | 47d59b48999 |
15 | 245907817e8 |
hex | 133ab7e29cb |
1321432132043 has 2 divisors, whose sum is σ = 1321432132044. Its totient is φ = 1321432132042.
The previous prime is 1321432131997. The next prime is 1321432132067. The reversal of 1321432132043 is 3402312341231.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1321432132043 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1321432131997 and 1321432132015.
It is not a weakly prime, because it can be changed into another prime (1321432132093) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660716066021 + 660716066022.
It is an arithmetic number, because the mean of its divisors is an integer number (660716066022).
Almost surely, 21321432132043 is an apocalyptic number.
1321432132043 is a deficient number, since it is larger than the sum of its proper divisors (1).
1321432132043 is an equidigital number, since it uses as much as digits as its factorization.
1321432132043 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10368, while the sum is 29.
Adding to 1321432132043 its reverse (3402312341231), we get a palindrome (4723744473274).
The spelling of 1321432132043 in words is "one trillion, three hundred twenty-one billion, four hundred thirty-two million, one hundred thirty-two thousand, forty-three".
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