Base | Representation |
---|---|
bin | 10011001110101011011… |
… | …111100010100110011101 |
3 | 11200022211212200120020201 |
4 | 103032223133202212131 |
5 | 133122243111210442 |
6 | 2451020232343501 |
7 | 164320214536255 |
oct | 23165337424635 |
9 | 4608755616221 |
10 | 1321432131997 |
11 | 46a463a9717a |
12 | 194128b44b91 |
13 | 977c23c1053 |
14 | 47d59b48965 |
15 | 245907817b7 |
hex | 133ab7e299d |
1321432131997 has 2 divisors, whose sum is σ = 1321432131998. Its totient is φ = 1321432131996.
The previous prime is 1321432131983. The next prime is 1321432132043. The reversal of 1321432131997 is 7991312341231.
It is an a-pointer prime, because the next prime (1321432132043) can be obtained adding 1321432131997 to its sum of digits (46).
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 862955534116 + 458476597881 = 928954^2 + 677109^2 .
It is a cyclic number.
It is not a de Polignac number, because 1321432131997 - 219 = 1321431607709 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1321432131907) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 660716065998 + 660716065999.
It is an arithmetic number, because the mean of its divisors is an integer number (660716065999).
Almost surely, 21321432131997 is an apocalyptic number.
It is an amenable number.
1321432131997 is a deficient number, since it is larger than the sum of its proper divisors (1).
1321432131997 is an equidigital number, since it uses as much as digits as its factorization.
1321432131997 is an evil number, because the sum of its binary digits is even.
The product of its digits is 244944, while the sum is 46.
The spelling of 1321432131997 in words is "one trillion, three hundred twenty-one billion, four hundred thirty-two million, one hundred thirty-one thousand, nine hundred ninety-seven".
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