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13214324131 is a prime number
BaseRepresentation
bin11000100111010001…
…01001010110100011
31021002221002012220021
430103220221112203
5204030331333011
610023124454311
7645314621221
oct142350512643
937087065807
1013214324131
115671161338
12268954a397
131327902b08
148d4dd9b11
1552518a471
hex313a295a3

13214324131 has 2 divisors, whose sum is σ = 13214324132. Its totient is φ = 13214324130.

The previous prime is 13214324129. The next prime is 13214324141. The reversal of 13214324131 is 13142341231.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13214324131 - 21 = 13214324129 is a prime.

It is a super-2 number, since 2×132143241312 (a number of 21 digits) contains 22 as substring.

Together with 13214324129, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 13214324096 and 13214324105.

It is not a weakly prime, because it can be changed into another prime (13214324141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6607162065 + 6607162066.

It is an arithmetic number, because the mean of its divisors is an integer number (6607162066).

Almost surely, 213214324131 is an apocalyptic number.

13214324131 is a deficient number, since it is larger than the sum of its proper divisors (1).

13214324131 is an equidigital number, since it uses as much as digits as its factorization.

13214324131 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1728, while the sum is 25.

Adding to 13214324131 its reverse (13142341231), we get a palindrome (26356665362).

The spelling of 13214324131 in words is "thirteen billion, two hundred fourteen million, three hundred twenty-four thousand, one hundred thirty-one".