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132143314201 = 235745361487
BaseRepresentation
bin111101100010001011…
…0101111010100011001
3110122002021221212222021
41323010112233110121
54131112142023301
6140412241454441
712355430431543
oct1730426572431
9418067855867
10132143314201
1151050501888
122173a641421
13c5cbc498a2
146577dcc693
1536860d48a1
hex1ec45af519

132143314201 has 4 divisors (see below), whose sum is σ = 137888675712. Its totient is φ = 126397952692.

The previous prime is 132143314153. The next prime is 132143314223. The reversal of 132143314201 is 102413341231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 102413341231 = 104759977609.

It is a cyclic number.

It is not a de Polignac number, because 132143314201 - 29 = 132143313689 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (132143314231) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2872680721 + ... + 2872680766.

It is an arithmetic number, because the mean of its divisors is an integer number (34472168928).

Almost surely, 2132143314201 is an apocalyptic number.

It is an amenable number.

132143314201 is a deficient number, since it is larger than the sum of its proper divisors (5745361511).

132143314201 is an equidigital number, since it uses as much as digits as its factorization.

132143314201 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5745361510.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 132143314201 its reverse (102413341231), we get a palindrome (234556655432).

The spelling of 132143314201 in words is "one hundred thirty-two billion, one hundred forty-three million, three hundred fourteen thousand, two hundred one".

Divisors: 1 23 5745361487 132143314201