Base | Representation |
---|---|
bin | 11110000010111100001010… |
… | …010001101101100101000010 |
3 | 122022212210021220222121120012 |
4 | 132002330022101231211002 |
5 | 114310014221342230310 |
6 | 1145013504303344522 |
7 | 36556022261325440 |
oct | 3602741221554502 |
9 | 568783256877505 |
10 | 132143431211330 |
11 | 39117794a45aa0 |
12 | 129a23478b2142 |
13 | 58970c25117b6 |
14 | 248bac1c4db90 |
15 | 1042549617c05 |
hex | 782f0a46d942 |
132143431211330 has 64 divisors (see below), whose sum is σ = 306776331175680. Its totient is φ = 39767302176000.
The previous prime is 132143431211321. The next prime is 132143431211347. The reversal of 132143431211330 is 33112134341231.
It is a super-2 number, since 2×1321434312113302 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2958854321 + ... + 2958898980.
It is an arithmetic number, because the mean of its divisors is an integer number (4793380174620).
Almost surely, 2132143431211330 is an apocalyptic number.
132143431211330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
132143431211330 is an abundant number, since it is smaller than the sum of its proper divisors (174632899964350).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
132143431211330 is a wasteful number, since it uses less digits than its factorization.
132143431211330 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5917753355.
The product of its (nonzero) digits is 15552, while the sum is 32.
Adding to 132143431211330 its reverse (33112134341231), we get a palindrome (165255565552561).
The spelling of 132143431211330 in words is "one hundred thirty-two trillion, one hundred forty-three billion, four hundred thirty-one million, two hundred eleven thousand, three hundred thirty".
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