Base | Representation |
---|---|
bin | 1100000001001011010011… |
… | …0101001000110111001111 |
3 | 1201210021112222220220121120 |
4 | 3000102310311020313033 |
5 | 3213000443411400221 |
6 | 44034331242132023 |
7 | 2532463664120001 |
oct | 300226465106717 |
9 | 51707488826546 |
10 | 13214353231311 |
11 | 42351a29a1031 |
12 | 15950441b1013 |
13 | 74b15383136b |
14 | 33981448c371 |
15 | 17db07c655c6 |
hex | c04b4d48dcf |
13214353231311 has 4 divisors (see below), whose sum is σ = 17619137641752. Its totient is φ = 8809568820872.
The previous prime is 13214353231291. The next prime is 13214353231319. The reversal of 13214353231311 is 11313235341231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13214353231311 - 226 = 13214286122447 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13214353231319) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2202392205216 + ... + 2202392205221.
It is an arithmetic number, because the mean of its divisors is an integer number (4404784410438).
Almost surely, 213214353231311 is an apocalyptic number.
13214353231311 is a deficient number, since it is larger than the sum of its proper divisors (4404784410441).
13214353231311 is an equidigital number, since it uses as much as digits as its factorization.
13214353231311 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4404784410440.
The product of its digits is 19440, while the sum is 33.
Adding to 13214353231311 its reverse (11313235341231), we get a palindrome (24527588572542).
The spelling of 13214353231311 in words is "thirteen trillion, two hundred fourteen billion, three hundred fifty-three million, two hundred thirty-one thousand, three hundred eleven".
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