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13214353250597 is a prime number
BaseRepresentation
bin1100000001001011010011…
…0101001101100100100101
31201210021112222221220001212
43000102310311031210211
53213000443413004342
644034331242401205
72532463664230142
oct300226465154445
951707488856055
1013214353250597
1142351a2a04574
121595044200205
1374b15383a085
143398144953c9
1517db07c6b182
hexc04b4d4d925

13214353250597 has 2 divisors, whose sum is σ = 13214353250598. Its totient is φ = 13214353250596.

The previous prime is 13214353250591. The next prime is 13214353250629. The reversal of 13214353250597 is 79505235341231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9825804928996 + 3388548321601 = 3134614^2 + 1840801^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13214353250597 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13214353250591) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6607176625298 + 6607176625299.

It is an arithmetic number, because the mean of its divisors is an integer number (6607176625299).

Almost surely, 213214353250597 is an apocalyptic number.

It is an amenable number.

13214353250597 is a deficient number, since it is larger than the sum of its proper divisors (1).

13214353250597 is an equidigital number, since it uses as much as digits as its factorization.

13214353250597 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3402000, while the sum is 50.

The spelling of 13214353250597 in words is "thirteen trillion, two hundred fourteen billion, three hundred fifty-three million, two hundred fifty thousand, five hundred ninety-seven".