13214353251139 has 2 divisors, whose sum is σ = 13214353251140. Its totient is φ = 13214353251138.

The previous prime is 13214353251109. The next prime is 13214353251173. The reversal of 13214353251139 is 93115235341231.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13214353251139 - 2¹³ = 13214353242947 is a prime.

It is a super-4 number, since 4×13214353251139⁴ (a number of 54 digits) contains 4444 as substring. Note that it is a super-d number also for d = 3.

It is a junction number, because it is equal to n+sod(n) for n = 13214353251095 and 13214353251104.

It is not a weakly prime, because it can be changed into another prime (13214353251109) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6607176625569 + 6607176625570.

It is an arithmetic number, because the mean of its divisors is an integer number (6607176625570).

Almost surely, 2^{13214353251139} is an apocalyptic number.

13214353251139 is a deficient number, since it is larger than the sum of its proper divisors (1).

13214353251139 is an equidigital number, since it uses as much as digits as its factorization.

13214353251139 is an evil number, because the sum of its binary digits is even.

The product of its digits is 291600, while the sum is 43.

The spelling of 13214353251139 in words is "thirteen trillion, two hundred fourteen billion, three hundred fifty-three million, two hundred fifty-one thousand, one hundred thirty-nine".