Base | Representation |
---|---|
bin | 1100000001001011010011… |
… | …0101001101101100100101 |
3 | 1201210021112222221220202211 |
4 | 3000102310311031230211 |
5 | 3213000443413013414 |
6 | 44034331242403421 |
7 | 2532463664231503 |
oct | 300226465155445 |
9 | 51707488856684 |
10 | 13214353251109 |
11 | 42351a2a0499a |
12 | 1595044200571 |
13 | 74b15383a38a |
14 | 339814495673 |
15 | 17db07c6b3c4 |
hex | c04b4d4db25 |
13214353251109 has 2 divisors, whose sum is σ = 13214353251110. Its totient is φ = 13214353251108.
The previous prime is 13214353251013. The next prime is 13214353251139. The reversal of 13214353251109 is 90115235341231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13093520539009 + 120832712100 = 3618497^2 + 347610^2 .
It is a cyclic number.
It is not a de Polignac number, because 13214353251109 - 29 = 13214353250597 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13214353251139) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6607176625554 + 6607176625555.
It is an arithmetic number, because the mean of its divisors is an integer number (6607176625555).
Almost surely, 213214353251109 is an apocalyptic number.
It is an amenable number.
13214353251109 is a deficient number, since it is larger than the sum of its proper divisors (1).
13214353251109 is an equidigital number, since it uses as much as digits as its factorization.
13214353251109 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 97200, while the sum is 40.
The spelling of 13214353251109 in words is "thirteen trillion, two hundred fourteen billion, three hundred fifty-three million, two hundred fifty-one thousand, one hundred nine".
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