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132144020510303 = 992913308895207
BaseRepresentation
bin11110000010111100101101…
…011001101101011001011111
3122022212211210222212002210002
4132002330231121231121133
5114310021423222312203
61145014042554204515
736556043005305314
oct3602745531553137
9568784728762702
10132144020510303
1139117a6765503a
12129a249112373b
135897187631709
14248bb3a20cd0b
15104258121ed88
hex782f2d66d65f

132144020510303 has 4 divisors (see below), whose sum is σ = 132157329415440. Its totient is φ = 132130711605168.

The previous prime is 132144020510179. The next prime is 132144020510321. The reversal of 132144020510303 is 303015020441231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 132144020510303 - 236 = 132075301033567 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132144020510363) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6654437675 + ... + 6654457532.

It is an arithmetic number, because the mean of its divisors is an integer number (33039332353860).

Almost surely, 2132144020510303 is an apocalyptic number.

132144020510303 is a deficient number, since it is larger than the sum of its proper divisors (13308905137).

132144020510303 is an equidigital number, since it uses as much as digits as its factorization.

132144020510303 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13308905136.

The product of its (nonzero) digits is 8640, while the sum is 29.

Adding to 132144020510303 its reverse (303015020441231), we get a palindrome (435159040951534).

The spelling of 132144020510303 in words is "one hundred thirty-two trillion, one hundred forty-four billion, twenty million, five hundred ten thousand, three hundred three".

Divisors: 1 9929 13308895207 132144020510303