1321440476149 has 4 divisors (see below), whose sum is σ = 1331527808160. Its totient is φ = 1311353144140.

The previous prime is 1321440476143. The next prime is 1321440476183. The reversal of 1321440476149 is 9416740441231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1321440476149 - 2¹⁵ = 1321440443381 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1321440476099 and 1321440476108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1321440476143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5043665809 + ... + 5043666070.

It is an arithmetic number, because the mean of its divisors is an integer number (332881952040).

Almost surely, 2^{1321440476149} is an apocalyptic number.

It is an amenable number.

1321440476149 is a deficient number, since it is larger than the sum of its proper divisors (10087332011).

1321440476149 is a wasteful number, since it uses less digits than its factorization.

1321440476149 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10087332010.

The product of its (nonzero) digits is 580608, while the sum is 46.

The spelling of 1321440476149 in words is "one trillion, three hundred twenty-one billion, four hundred forty million, four hundred seventy-six thousand, one hundred forty-nine".