132144132540555 has 12 divisors (see below), whose sum is σ = 229049829737040. Its totient is φ = 70476870688272.

The previous prime is 132144132540533. The next prime is 132144132540571. The reversal of 132144132540555 is 555045231441231.

132144132540555 is a `hidden beast` number, since 1 + 3 + 2 + 1 + 4 + 41 + 3 + 2 + 54 + 0 + 555 = 666.

It is a de Polignac number, because none of the positive numbers 2^k-132144132540555 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (45), and also a Moran number because the ratio is a prime number: 2936536278679 = 132144132540555 / (1 + 3 + 2 + 1 + 4 + 4 + 1 + 3 + 2 + 5 + 4 + 0 + 5 + 5 + 5).

It is a self number, because there is not a number n which added to its sum of digits gives 132144132540555.

It is an unprimeable number.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1468268139295 + ... + 1468268139384.

It is an arithmetic number, because the mean of its divisors is an integer number (19087485811420).

Almost surely, 2^{132144132540555} is an apocalyptic number.

132144132540555 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

132144132540555 is a deficient number, since it is larger than the sum of its proper divisors (96905697196485).

132144132540555 is a wasteful number, since it uses less digits than its factorization.

132144132540555 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2936536278690 (or 2936536278687 counting only the distinct ones).

The product of its (nonzero) digits is 1440000, while the sum is 45.

Adding to 132144132540555 its reverse (555045231441231), we get a palindrome (687189363981786).

The spelling of 132144132540555 in words is "one hundred thirty-two trillion, one hundred forty-four billion, one hundred thirty-two million, five hundred forty thousand, five hundred fifty-five".