Base | Representation |
---|---|
bin | 11000100111010010… |
… | …10111000011100111 |
3 | 1021002221102201200202 |
4 | 30103221113003213 |
5 | 204030403330320 |
6 | 10023132501115 |
7 | 645316331054 |
oct | 142351270347 |
9 | 37087381622 |
10 | 13214511335 |
11 | 5671279a53 |
12 | 268961a79b |
13 | 132796a09c |
14 | 8d504802b |
15 | 5251c5b75 |
hex | 313a570e7 |
13214511335 has 16 divisors (see below), whose sum is σ = 16308081216. Its totient is φ = 10271939328.
The previous prime is 13214511307. The next prime is 13214511347. The reversal of 13214511335 is 53311541231.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13214511335 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13214511298 and 13214511307.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 89387 + ... + 185523.
It is an arithmetic number, because the mean of its divisors is an integer number (1019255076).
Almost surely, 213214511335 is an apocalyptic number.
13214511335 is a deficient number, since it is larger than the sum of its proper divisors (3093569881).
13214511335 is an equidigital number, since it uses as much as digits as its factorization.
13214511335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 96922.
The product of its digits is 5400, while the sum is 29.
The spelling of 13214511335 in words is "thirteen billion, two hundred fourteen million, five hundred eleven thousand, three hundred thirty-five".
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