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132145401734 = 266072700867
BaseRepresentation
bin111101100010001111…
…0101100111110000110
3110122002102212221112022
41323010132230332012
54131113210323414
6140412354323142
712355454244623
oct1730436547606
9418072787468
10132145401734
11510516a8215
122173b2894b2
13c5cc4cab08
1465783b334a
15368639818e
hex1ec47acf86

132145401734 has 4 divisors (see below), whose sum is σ = 198218102604. Its totient is φ = 66072700866.

The previous prime is 132145401673. The next prime is 132145401757. The reversal of 132145401734 is 437104541231.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 437104541231 = 2320318838277.

It is a junction number, because it is equal to n+sod(n) for n = 132145401694 and 132145401703.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33036350432 + ... + 33036350435.

It is an arithmetic number, because the mean of its divisors is an integer number (49554525651).

Almost surely, 2132145401734 is an apocalyptic number.

132145401734 is a deficient number, since it is larger than the sum of its proper divisors (66072700870).

132145401734 is an equidigital number, since it uses as much as digits as its factorization.

132145401734 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 66072700869.

The product of its (nonzero) digits is 40320, while the sum is 35.

Adding to 132145401734 its reverse (437104541231), we get a palindrome (569249942965).

The spelling of 132145401734 in words is "one hundred thirty-two billion, one hundred forty-five million, four hundred one thousand, seven hundred thirty-four".

Divisors: 1 2 66072700867 132145401734