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132146445160127 is a prime number
BaseRepresentation
bin11110000010111110111101…
…111011000000111010111111
3122022220002001222021002001102
4132002332331323000322333
5114310041404430111002
61145015123331003315
736556160046425246
oct3602767573007277
9568802058232042
10132146445160127
1139118aa1273372
12129a2a4913953b
135897482a6b058
14248bcca24795d
151042674014a02
hex782fbdec0ebf

132146445160127 has 2 divisors, whose sum is σ = 132146445160128. Its totient is φ = 132146445160126.

The previous prime is 132146445160091. The next prime is 132146445160133. The reversal of 132146445160127 is 721061544641231.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 132146445160127 - 212 = 132146445156031 is a prime.

It is a super-2 number, since 2×1321464451601272 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132146442160127) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66073222580063 + 66073222580064.

It is an arithmetic number, because the mean of its divisors is an integer number (66073222580064).

Almost surely, 2132146445160127 is an apocalyptic number.

132146445160127 is a deficient number, since it is larger than the sum of its proper divisors (1).

132146445160127 is an equidigital number, since it uses as much as digits as its factorization.

132146445160127 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 967680, while the sum is 47.

The spelling of 132146445160127 in words is "one hundred thirty-two trillion, one hundred forty-six billion, four hundred forty-five million, one hundred sixty thousand, one hundred twenty-seven".