Base | Representation |
---|---|
bin | 11110000011000010110111… |
… | …100100101111001110111111 |
3 | 122022220110212212121010000221 |
4 | 132003002313210233032333 |
5 | 114310123444201441021 |
6 | 1145021055112202211 |
7 | 36556365615662545 |
oct | 3603026744571677 |
9 | 568813785533027 |
10 | 132150633624511 |
11 | 3911a850580687 |
12 | 129a3817999367 |
13 | 589799c738248 |
14 | 248c1a6619d95 |
15 | 104281bab6241 |
hex | 7830b792f3bf |
132150633624511 has 4 divisors (see below), whose sum is σ = 132150788841112. Its totient is φ = 132150478407912.
The previous prime is 132150633624509. The next prime is 132150633624557. The reversal of 132150633624511 is 115426336051231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 132150633624511 - 21 = 132150633624509 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132150633024511) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 76324125 + ... + 78036358.
It is an arithmetic number, because the mean of its divisors is an integer number (33037697210278).
Almost surely, 2132150633624511 is an apocalyptic number.
132150633624511 is a deficient number, since it is larger than the sum of its proper divisors (155216601).
132150633624511 is an equidigital number, since it uses as much as digits as its factorization.
132150633624511 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 155216600.
The product of its (nonzero) digits is 388800, while the sum is 43.
Adding to 132150633624511 its reverse (115426336051231), we get a palindrome (247576969675742).
The spelling of 132150633624511 in words is "one hundred thirty-two trillion, one hundred fifty billion, six hundred thirty-three million, six hundred twenty-four thousand, five hundred eleven".
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