Base | Representation |
---|---|
bin | 11110000011000010111000… |
… | …101001100001010001001011 |
3 | 122022220110221010112011112211 |
4 | 132003002320221201101023 |
5 | 114310124013310431433 |
6 | 1145021100554445551 |
7 | 36556366225150354 |
oct | 3603027051412113 |
9 | 568813833464484 |
10 | 132150651655243 |
11 | 3911a85a776411 |
12 | 129a3821a338b7 |
13 | 58979a33ac210 |
14 | 248c1a8b90d2b |
15 | 104281d4788cd |
hex | 7830b8a6144b |
132150651655243 has 4 divisors (see below), whose sum is σ = 142316086397968. Its totient is φ = 121985216912520.
The previous prime is 132150651655229. The next prime is 132150651655249. The reversal of 132150651655243 is 342556156051231.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 132150651655243 - 233 = 132142061720651 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (132150651655249) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5082717371343 + ... + 5082717371368.
It is an arithmetic number, because the mean of its divisors is an integer number (35579021599492).
Almost surely, 2132150651655243 is an apocalyptic number.
132150651655243 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
132150651655243 is a deficient number, since it is larger than the sum of its proper divisors (10165434742725).
132150651655243 is a wasteful number, since it uses less digits than its factorization.
132150651655243 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10165434742724.
The product of its (nonzero) digits is 3240000, while the sum is 49.
The spelling of 132150651655243 in words is "one hundred thirty-two trillion, one hundred fifty billion, six hundred fifty-one million, six hundred fifty-five thousand, two hundred forty-three".
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