Base | Representation |
---|---|
bin | 11110000011000011010101… |
… | …001110010001100101000001 |
3 | 122022220112011112121001202100 |
4 | 132003003111032101211001 |
5 | 114310131004022133403 |
6 | 1145021220321541013 |
7 | 36556414136024520 |
oct | 3603032516214501 |
9 | 568815145531670 |
10 | 132151131052353 |
11 | 3911aa86340576 |
12 | 129a39364a4769 |
13 | 5897a4b7cc64a |
14 | 248c2127024b7 |
15 | 104284a5c22a3 |
hex | 7830d5391941 |
132151131052353 has 12 divisors (see below), whose sum is σ = 218154248086528. Its totient is φ = 75514932029880.
The previous prime is 132151131052333. The next prime is 132151131052397. The reversal of 132151131052353 is 353250131151231.
132151131052353 is a `hidden beast` number, since 1 + 3 + 2 + 1 + 5 + 113 + 10 + 523 + 5 + 3 = 666.
It is not a de Polignac number, because 132151131052353 - 213 = 132151131044161 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (132151131052333) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1048818500353 + ... + 1048818500478.
Almost surely, 2132151131052353 is an apocalyptic number.
It is an amenable number.
132151131052353 is a deficient number, since it is larger than the sum of its proper divisors (86003117034175).
132151131052353 is a wasteful number, since it uses less digits than its factorization.
132151131052353 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2097637000844 (or 2097637000841 counting only the distinct ones).
The product of its (nonzero) digits is 40500, while the sum is 36.
The spelling of 132151131052353 in words is "one hundred thirty-two trillion, one hundred fifty-one billion, one hundred thirty-one million, fifty-two thousand, three hundred fifty-three".
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