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132151142531351 = 463285423633977
BaseRepresentation
bin11110000011000011010101…
…111010000100000100010111
3122022220112012100012020222102
4132003003111322010010113
5114310131014442000401
61145021221411552315
736556414335424136
oct3603032572040427
9568815170166872
10132151142531351
113911aa91870949
12129a393a2bb69b
135897a50cbb458
14248c21404d91d
15104284b5dd56b
hex7830d5e84117

132151142531351 has 4 divisors (see below), whose sum is σ = 132436566165792. Its totient is φ = 131865718896912.

The previous prime is 132151142531333. The next prime is 132151142531363. The reversal of 132151142531351 is 153135241151231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-132151142531351 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132151142531311) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 142711816526 + ... + 142711817451.

It is an arithmetic number, because the mean of its divisors is an integer number (33109141541448).

Almost surely, 2132151142531351 is an apocalyptic number.

132151142531351 is a deficient number, since it is larger than the sum of its proper divisors (285423634441).

132151142531351 is an equidigital number, since it uses as much as digits as its factorization.

132151142531351 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 285423634440.

The product of its digits is 54000, while the sum is 38.

Adding to 132151142531351 its reverse (153135241151231), we get a palindrome (285286383682582).

The spelling of 132151142531351 in words is "one hundred thirty-two trillion, one hundred fifty-one billion, one hundred forty-two million, five hundred thirty-one thousand, three hundred fifty-one".

Divisors: 1 463 285423633977 132151142531351