Base | Representation |
---|---|
bin | 11110000011000101010100… |
… | …001001101011000100010111 |
3 | 122022220201122221121212202002 |
4 | 132003011110021223010113 |
5 | 114310144334200134341 |
6 | 1145022211512305515 |
7 | 36556520664335624 |
oct | 3603052411530427 |
9 | 568821587555662 |
10 | 132153260552471 |
11 | 39120979398524 |
12 | 129a422b6a229b |
13 | 5897ccaa48aa2 |
14 | 248c37546b34b |
15 | 104292251529b |
hex | 78315426b117 |
132153260552471 has 2 divisors, whose sum is σ = 132153260552472. Its totient is φ = 132153260552470.
The previous prime is 132153260552441. The next prime is 132153260552477. The reversal of 132153260552471 is 174255062351231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132153260552471 - 218 = 132153260290327 is a prime.
It is a super-3 number, since 3×1321532605524713 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132153260552477) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66076630276235 + 66076630276236.
It is an arithmetic number, because the mean of its divisors is an integer number (66076630276236).
Almost surely, 2132153260552471 is an apocalyptic number.
132153260552471 is a deficient number, since it is larger than the sum of its proper divisors (1).
132153260552471 is an equidigital number, since it uses as much as digits as its factorization.
132153260552471 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1512000, while the sum is 47.
The spelling of 132153260552471 in words is "one hundred thirty-two trillion, one hundred fifty-three billion, two hundred sixty million, five hundred fifty-two thousand, four hundred seventy-one".
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