Base | Representation |
---|---|
bin | 11110000011000101011110… |
… | …111011111111000010110010 |
3 | 122022220202010120010122210222 |
4 | 132003011132323333002302 |
5 | 114310200222011414100 |
6 | 1145022241455053042 |
7 | 36556525322436344 |
oct | 3603053673770262 |
9 | 568822116118728 |
10 | 132153441513650 |
11 | 39120a61557317 |
12 | 129a4280211182 |
13 | 58980293982cb |
14 | 248c3914d5294 |
15 | 104293335d485 |
hex | 78315eeff0b2 |
132153441513650 has 24 divisors (see below), whose sum is σ = 247092340506624. Its totient is φ = 52584615467600.
The previous prime is 132153441513637. The next prime is 132153441513683. The reversal of 132153441513650 is 56315144351231.
It is a super-2 number, since 2×1321534415136502 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 6919018802 + ... + 6919037901.
It is an arithmetic number, because the mean of its divisors is an integer number (10295514187776).
Almost surely, 2132153441513650 is an apocalyptic number.
132153441513650 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
132153441513650 is a deficient number, since it is larger than the sum of its proper divisors (114938898992974).
132153441513650 is a wasteful number, since it uses less digits than its factorization.
132153441513650 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 13838056906 (or 13838056901 counting only the distinct ones).
The product of its (nonzero) digits is 648000, while the sum is 44.
Adding to 132153441513650 its reverse (56315144351231), we get a palindrome (188468585864881).
The spelling of 132153441513650 in words is "one hundred thirty-two trillion, one hundred fifty-three billion, four hundred forty-one million, five hundred thirteen thousand, six hundred fifty".
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