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132153442405447 is a prime number
BaseRepresentation
bin11110000011000101011110…
…111111011000110001000111
3122022220202010121210222010111
4132003011132333120301013
5114310200222223433242
61145022241530133451
736556525333142341
oct3603053677306107
9568822117728114
10132153442405447
1139120a62006341
12129a4280581287
13589802961b1b8
14248c391688291
151042933487817
hex78315efd8c47

132153442405447 has 2 divisors, whose sum is σ = 132153442405448. Its totient is φ = 132153442405446.

The previous prime is 132153442405403. The next prime is 132153442405493. The reversal of 132153442405447 is 744504244351231.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 132153442405447 - 27 = 132153442405319 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 132153442405447.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132153142405447) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66076721202723 + 66076721202724.

It is an arithmetic number, because the mean of its divisors is an integer number (66076721202724).

Almost surely, 2132153442405447 is an apocalyptic number.

132153442405447 is a deficient number, since it is larger than the sum of its proper divisors (1).

132153442405447 is an equidigital number, since it uses as much as digits as its factorization.

132153442405447 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6451200, while the sum is 49.

Adding to 132153442405447 its reverse (744504244351231), we get a palindrome (876657686756678).

The spelling of 132153442405447 in words is "one hundred thirty-two trillion, one hundred fifty-three billion, four hundred forty-two million, four hundred five thousand, four hundred forty-seven".