Search a number
-
+
132153442411351 = 322514097654101
BaseRepresentation
bin11110000011000101011110…
…111111011010001101010111
3122022220202010121211021020011
4132003011132333122031113
5114310200222224130401
61145022241530221051
736556525333165504
oct3603053677321527
9568822117737204
10132153442411351
1139120a6200a819
12129a4280584787
135898029620aaa
14248c39168a4ab
151042933489451
hex78315efda357

132153442411351 has 4 divisors (see below), whose sum is σ = 132157540097704. Its totient is φ = 132149344725000.

The previous prime is 132153442411343. The next prime is 132153442411373. The reversal of 132153442411351 is 153114244351231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 132153442411351 - 23 = 132153442411343 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132153442411391) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2048794800 + ... + 2048859301.

It is an arithmetic number, because the mean of its divisors is an integer number (33039385024426).

Almost surely, 2132153442411351 is an apocalyptic number.

132153442411351 is a deficient number, since it is larger than the sum of its proper divisors (4097686353).

132153442411351 is an equidigital number, since it uses as much as digits as its factorization.

132153442411351 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4097686352.

The product of its digits is 172800, while the sum is 40.

Adding to 132153442411351 its reverse (153114244351231), we get a palindrome (285267686762582).

The spelling of 132153442411351 in words is "one hundred thirty-two trillion, one hundred fifty-three billion, four hundred forty-two million, four hundred eleven thousand, three hundred fifty-one".

Divisors: 1 32251 4097654101 132153442411351