Base | Representation |
---|---|
bin | 11110000011000101011110… |
… | …111111110101100101101111 |
3 | 122022220202010122000222001221 |
4 | 132003011132333311211233 |
5 | 114310200222241223003 |
6 | 1145022241532444211 |
7 | 36556525334143462 |
oct | 3603053677654557 |
9 | 568822118028057 |
10 | 132153442523503 |
11 | 39120a62087005 |
12 | 129a4280619667 |
13 | 589802965cb5b |
14 | 248c3916b92d9 |
15 | 10429334ac7bd |
hex | 78315eff596f |
132153442523503 has 2 divisors, whose sum is σ = 132153442523504. Its totient is φ = 132153442523502.
The previous prime is 132153442523497. The next prime is 132153442523603. The reversal of 132153442523503 is 305325244351231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 132153442523503 - 25 = 132153442523471 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 132153442523503.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132153442523603) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66076721261751 + 66076721261752.
It is an arithmetic number, because the mean of its divisors is an integer number (66076721261752).
Almost surely, 2132153442523503 is an apocalyptic number.
132153442523503 is a deficient number, since it is larger than the sum of its proper divisors (1).
132153442523503 is an equidigital number, since it uses as much as digits as its factorization.
132153442523503 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296000, while the sum is 43.
Adding to 132153442523503 its reverse (305325244351231), we get a palindrome (437478686874734).
The spelling of 132153442523503 in words is "one hundred thirty-two trillion, one hundred fifty-three billion, four hundred forty-two million, five hundred twenty-three thousand, five hundred three".
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