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132153464510413 is a prime number
BaseRepresentation
bin11110000011000101100000…
…010011101101011111001101
3122022220202012011102000102221
4132003011200103231133031
5114310200243403313123
61145022244040015341
736556526022056323
oct3603054023553715
9568822164360387
10132153464510413
1139120a73534105
12129a4287a61551
13589803108a768
14248c39459dd13
1510429353a225d
hex7831604ed7cd

132153464510413 has 2 divisors, whose sum is σ = 132153464510414. Its totient is φ = 132153464510412.

The previous prime is 132153464510407. The next prime is 132153464510437. The reversal of 132153464510413 is 314015464351231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 131686021555209 + 467442955204 = 11475453^2 + 683698^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-132153464510413 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 132153464510413.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132153464510453) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66076732255206 + 66076732255207.

It is an arithmetic number, because the mean of its divisors is an integer number (66076732255207).

Almost surely, 2132153464510413 is an apocalyptic number.

It is an amenable number.

132153464510413 is a deficient number, since it is larger than the sum of its proper divisors (1).

132153464510413 is an equidigital number, since it uses as much as digits as its factorization.

132153464510413 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 518400, while the sum is 43.

The spelling of 132153464510413 in words is "one hundred thirty-two trillion, one hundred fifty-three billion, four hundred sixty-four million, five hundred ten thousand, four hundred thirteen".