Search a number
-
+
132153465411481 is a prime number
BaseRepresentation
bin11110000011000101100000…
…010111001001011110011001
3122022220202012020002210110211
4132003011200113021132121
5114310200244121131411
61145022244111211121
736556526032531333
oct3603054027113631
9568822166083424
10132153465411481
1139120a73a9a098
12129a4288216aa1
135898031314937
14248c394756453
1510429354ce221
hex7831605c9799

132153465411481 has 2 divisors, whose sum is σ = 132153465411482. Its totient is φ = 132153465411480.

The previous prime is 132153465411439. The next prime is 132153465411547. The reversal of 132153465411481 is 184114564351231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 78037506525456 + 54115958886025 = 8833884^2 + 7356355^2 .

It is a cyclic number.

It is not a de Polignac number, because 132153465411481 - 219 = 132153464887193 is a prime.

It is a super-2 number, since 2×1321534654114812 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (132153465411181) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66076732705740 + 66076732705741.

It is an arithmetic number, because the mean of its divisors is an integer number (66076732705741).

Almost surely, 2132153465411481 is an apocalyptic number.

It is an amenable number.

132153465411481 is a deficient number, since it is larger than the sum of its proper divisors (1).

132153465411481 is an equidigital number, since it uses as much as digits as its factorization.

132153465411481 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1382400, while the sum is 49.

The spelling of 132153465411481 in words is "one hundred thirty-two trillion, one hundred fifty-three billion, four hundred sixty-five million, four hundred eleven thousand, four hundred eighty-one".