Base | Representation |
---|---|
bin | 11110000011000101100000… |
… | …010111001001011111011011 |
3 | 122022220202012020002210120021 |
4 | 132003011200113021133123 |
5 | 114310200244121132142 |
6 | 1145022244111211311 |
7 | 36556526032531456 |
oct | 3603054027113733 |
9 | 568822166083507 |
10 | 132153465411547 |
11 | 39120a73a9a148 |
12 | 129a4288216b37 |
13 | 5898031314988 |
14 | 248c39475649d |
15 | 10429354ce267 |
hex | 7831605c97db |
132153465411547 has 2 divisors, whose sum is σ = 132153465411548. Its totient is φ = 132153465411546.
The previous prime is 132153465411481. The next prime is 132153465411571. The reversal of 132153465411547 is 745114564351231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132153465411547 - 211 = 132153465409499 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 132153465411494 and 132153465411503.
It is not a weakly prime, because it can be changed into another prime (132153465411047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66076732705773 + 66076732705774.
It is an arithmetic number, because the mean of its divisors is an integer number (66076732705774).
Almost surely, 2132153465411547 is an apocalyptic number.
132153465411547 is a deficient number, since it is larger than the sum of its proper divisors (1).
132153465411547 is an equidigital number, since it uses as much as digits as its factorization.
132153465411547 is an evil number, because the sum of its binary digits is even.
The product of its digits is 6048000, while the sum is 52.
The spelling of 132153465411547 in words is "one hundred thirty-two trillion, one hundred fifty-three billion, four hundred sixty-five million, four hundred eleven thousand, five hundred forty-seven".
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