Base | Representation |
---|---|
bin | 10011001110110001101… |
… | …000110001111100101010 |
3 | 11200100010001122211220110 |
4 | 103032301220301330222 |
5 | 133123001003424300 |
6 | 2451034354035150 |
7 | 164322606002040 |
oct | 23166150617452 |
9 | 4610101584813 |
10 | 1321535217450 |
11 | 46a5071a5868 |
12 | 194157578ab6 |
13 | 9780a875066 |
14 | 47d69700390 |
15 | 24599845550 |
hex | 133b1a31f2a |
1321535217450 has 96 divisors (see below), whose sum is σ = 3832715690496. Its totient is φ = 295040410560.
The previous prime is 1321535217449. The next prime is 1321535217473. The reversal of 1321535217450 is 547125351231.
It is a junction number, because it is equal to n+sod(n) for n = 1321535217399 and 1321535217408.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 14589792 + ... + 14680091.
It is an arithmetic number, because the mean of its divisors is an integer number (39924121776).
Almost surely, 21321535217450 is an apocalyptic number.
1321535217450 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1321535217450 is an abundant number, since it is smaller than the sum of its proper divisors (2511180473046).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1321535217450 is a wasteful number, since it uses less digits than its factorization.
1321535217450 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 29269948 (or 29269943 counting only the distinct ones).
The product of its (nonzero) digits is 126000, while the sum is 39.
The spelling of 1321535217450 in words is "one trillion, three hundred twenty-one billion, five hundred thirty-five million, two hundred seventeen thousand, four hundred fifty".
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