Base | Representation |
---|---|
bin | 11110000011000101101010… |
… | …011011010001011000011011 |
3 | 122022220202121222211102102011 |
4 | 132003011222123101120123 |
5 | 114310201120332431403 |
6 | 1145022312542250351 |
7 | 36556533153002440 |
oct | 3603055233213033 |
9 | 568822558742364 |
10 | 132153634264603 |
11 | 39121050338a26 |
12 | 129a43148869b7 |
13 | 589805a2b4c23 |
14 | 248c3acd4b9c7 |
15 | 1042945234a6d |
hex | 78316a6d161b |
132153634264603 has 4 divisors (see below), whose sum is σ = 151032724873840. Its totient is φ = 113274543655368.
The previous prime is 132153634264543. The next prime is 132153634264609. The reversal of 132153634264603 is 306462436351231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132153634264603 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (132153634264609) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9439545304608 + ... + 9439545304621.
It is an arithmetic number, because the mean of its divisors is an integer number (37758181218460).
Almost surely, 2132153634264603 is an apocalyptic number.
132153634264603 is a deficient number, since it is larger than the sum of its proper divisors (18879090609237).
132153634264603 is an equidigital number, since it uses as much as digits as its factorization.
132153634264603 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 18879090609236.
The product of its (nonzero) digits is 5598720, while the sum is 49.
The spelling of 132153634264603 in words is "one hundred thirty-two trillion, one hundred fifty-three billion, six hundred thirty-four million, two hundred sixty-four thousand, six hundred three".
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