Base | Representation |
---|---|
bin | 1100000001001111001101… |
… | …0110010110011011001101 |
3 | 1201210101021002121020021011 |
4 | 3000103303112112123031 |
5 | 3213010120421000010 |
6 | 44035023311405221 |
7 | 2532531661430053 |
oct | 300236326263315 |
9 | 51711232536234 |
10 | 13215402125005 |
11 | 4235690a7a423 |
12 | 1595297523811 |
13 | 74b28cc2a212 |
14 | 3398b38c61d3 |
15 | 17db69da3a8a |
hex | c04f35966cd |
13215402125005 has 16 divisors (see below), whose sum is σ = 16370166528000. Its totient is φ = 10231204049280.
The previous prime is 13215402124961. The next prime is 13215402125027. The reversal of 13215402125005 is 50052120451231.
13215402125005 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a de Polignac number, because none of the positive numbers 2k-13215402125005 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (31).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 30950556 + ... + 31374634.
It is an arithmetic number, because the mean of its divisors is an integer number (1023135408000).
Almost surely, 213215402125005 is an apocalyptic number.
It is an amenable number.
13215402125005 is a deficient number, since it is larger than the sum of its proper divisors (3154764402995).
13215402125005 is a wasteful number, since it uses less digits than its factorization.
13215402125005 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 625164.
The product of its (nonzero) digits is 12000, while the sum is 31.
Adding to 13215402125005 its reverse (50052120451231), we get a palindrome (63267522576236).
The spelling of 13215402125005 in words is "thirteen trillion, two hundred fifteen billion, four hundred two million, one hundred twenty-five thousand, five".
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