Base | Representation |
---|---|
bin | 11110000011000111100000… |
… | …011001100000001100110111 |
3 | 122022220221201221010122002221 |
4 | 132003013200121200030313 |
5 | 114310214144024400003 |
6 | 1145023241204343211 |
7 | 36556633205223460 |
oct | 3603074031401467 |
9 | 568827657118087 |
10 | 132155613512503 |
11 | 391219765a1199 |
12 | 129a47876a4b07 |
13 | 58982b4374729 |
14 | 248c519b63d67 |
15 | 1042a0dd987bd |
hex | 7831e0660337 |
132155613512503 has 4 divisors (see below), whose sum is σ = 151034986871440. Its totient is φ = 113276240153568.
The previous prime is 132155613512501. The next prime is 132155613512543. The reversal of 132155613512503 is 305215316551231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 132155613512503 - 21 = 132155613512501 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 132155613512503.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132155613512501) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9439686679458 + ... + 9439686679471.
It is an arithmetic number, because the mean of its divisors is an integer number (37758746717860).
Almost surely, 2132155613512503 is an apocalyptic number.
132155613512503 is a deficient number, since it is larger than the sum of its proper divisors (18879373358937).
132155613512503 is an equidigital number, since it uses as much as digits as its factorization.
132155613512503 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 18879373358936.
The product of its (nonzero) digits is 405000, while the sum is 43.
The spelling of 132155613512503 in words is "one hundred thirty-two trillion, one hundred fifty-five billion, six hundred thirteen million, five hundred twelve thousand, five hundred three".
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