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132155613512503 = 718879373358929
BaseRepresentation
bin11110000011000111100000…
…011001100000001100110111
3122022220221201221010122002221
4132003013200121200030313
5114310214144024400003
61145023241204343211
736556633205223460
oct3603074031401467
9568827657118087
10132155613512503
11391219765a1199
12129a47876a4b07
1358982b4374729
14248c519b63d67
151042a0dd987bd
hex7831e0660337

132155613512503 has 4 divisors (see below), whose sum is σ = 151034986871440. Its totient is φ = 113276240153568.

The previous prime is 132155613512501. The next prime is 132155613512543. The reversal of 132155613512503 is 305215316551231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 132155613512503 - 21 = 132155613512501 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 132155613512503.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132155613512501) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9439686679458 + ... + 9439686679471.

It is an arithmetic number, because the mean of its divisors is an integer number (37758746717860).

Almost surely, 2132155613512503 is an apocalyptic number.

132155613512503 is a deficient number, since it is larger than the sum of its proper divisors (18879373358937).

132155613512503 is an equidigital number, since it uses as much as digits as its factorization.

132155613512503 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 18879373358936.

The product of its (nonzero) digits is 405000, while the sum is 43.

The spelling of 132155613512503 in words is "one hundred thirty-two trillion, one hundred fifty-five billion, six hundred thirteen million, five hundred twelve thousand, five hundred three".

Divisors: 1 7 18879373358929 132155613512503