Base | Representation |
---|---|
bin | 10011001110110011001… |
… | …010111100111001001001 |
3 | 11200100011212002022121111 |
4 | 103032303022330321021 |
5 | 133123024100434033 |
6 | 2451041113410321 |
7 | 164323340515033 |
oct | 23166312747111 |
9 | 4610155068544 |
10 | 1321560952393 |
11 | 46a51a782910 |
12 | 1941641099a1 |
13 | 97812cb5936 |
14 | 47d6ccbcc53 |
15 | 2459bc2a7cd |
hex | 133b32bce49 |
1321560952393 has 4 divisors (see below), whose sum is σ = 1441702857168. Its totient is φ = 1201419047620.
The previous prime is 1321560952351. The next prime is 1321560952427. The reversal of 1321560952393 is 3932590651231.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 1321560952393 - 237 = 1184121998921 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1321560956393) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 60070952371 + ... + 60070952392.
It is an arithmetic number, because the mean of its divisors is an integer number (360425714292).
Almost surely, 21321560952393 is an apocalyptic number.
It is an amenable number.
1321560952393 is a deficient number, since it is larger than the sum of its proper divisors (120141904775).
1321560952393 is a wasteful number, since it uses less digits than its factorization.
1321560952393 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 120141904774.
The product of its (nonzero) digits is 1312200, while the sum is 49.
The spelling of 1321560952393 in words is "one trillion, three hundred twenty-one billion, five hundred sixty million, nine hundred fifty-two thousand, three hundred ninety-three".
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