Base | Representation |
---|---|
bin | 11110000011001100111011… |
… | …010111010100100000111101 |
3 | 122022221111202121121021000120 |
4 | 132003030323113110200331 |
5 | 114310313104231244201 |
6 | 1145030042551245153 |
7 | 36560230361025162 |
oct | 3603147327244075 |
9 | 568844677537016 |
10 | 132161434634301 |
11 | 39124393456156 |
12 | 129a59310797b9 |
13 | 5898a013700b7 |
14 | 248c90cccc069 |
15 | 1042c4ee4a536 |
hex | 78333b5d483d |
132161434634301 has 8 divisors (see below), whose sum is σ = 176216268874464. Its totient is φ = 88107111741840.
The previous prime is 132161434634263. The next prime is 132161434634351. The reversal of 132161434634301 is 103436434161231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 132161434634301 - 214 = 132161434617917 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132161434634351) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 127233451 + ... + 128267976.
It is an arithmetic number, because the mean of its divisors is an integer number (22027033609308).
Almost surely, 2132161434634301 is an apocalyptic number.
It is an amenable number.
132161434634301 is a deficient number, since it is larger than the sum of its proper divisors (44054834240163).
132161434634301 is a wasteful number, since it uses less digits than its factorization.
132161434634301 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 255673851.
The product of its (nonzero) digits is 373248, while the sum is 42.
Adding to 132161434634301 its reverse (103436434161231), we get a palindrome (235597868795532).
The spelling of 132161434634301 in words is "one hundred thirty-two trillion, one hundred sixty-one billion, four hundred thirty-four million, six hundred thirty-four thousand, three hundred one".
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