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132161968280197 is a prime number
BaseRepresentation
bin11110000011001101011011…
…001011000001001010000101
3122022221120010210202021120101
4132003031123023001022011
5114310320202334431242
61145030211533204101
736560246530654132
oct3603153313011205
9568846123667511
10132161968280197
1139124637703219
12129a5a5b930631
135898a87aa57bb
14248c95db21589
151042c81c0c9b7
hex78335b2c1285

132161968280197 has 2 divisors, whose sum is σ = 132161968280198. Its totient is φ = 132161968280196.

The previous prime is 132161968280119. The next prime is 132161968280207. The reversal of 132161968280197 is 791082869161231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 75228318577476 + 56933649702721 = 8673426^2 + 7545439^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-132161968280197 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132161968280897) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66080984140098 + 66080984140099.

It is an arithmetic number, because the mean of its divisors is an integer number (66080984140099).

Almost surely, 2132161968280197 is an apocalyptic number.

It is an amenable number.

132161968280197 is a deficient number, since it is larger than the sum of its proper divisors (1).

132161968280197 is an equidigital number, since it uses as much as digits as its factorization.

132161968280197 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 15676416, while the sum is 64.

The spelling of 132161968280197 in words is "one hundred thirty-two trillion, one hundred sixty-one billion, nine hundred sixty-eight million, two hundred eighty thousand, one hundred ninety-seven".