Base | Representation |
---|---|
bin | 11110000011110001000010… |
… | …100011111111110000011011 |
3 | 122100002012211221111011210212 |
4 | 132003301002203333300123 |
5 | 114311432012241301243 |
6 | 1145055534344201335 |
7 | 36563102306050625 |
oct | 3603610243776033 |
9 | 570065757434725 |
10 | 132200210103323 |
11 | 39139881172a1a |
12 | 129b1352a6924b |
13 | 589c57081c5cb |
14 | 249074a9c1c15 |
15 | 1043c6e19d318 |
hex | 783c428ffc1b |
132200210103323 has 2 divisors, whose sum is σ = 132200210103324. Its totient is φ = 132200210103322.
The previous prime is 132200210103287. The next prime is 132200210103341. The reversal of 132200210103323 is 323301012002231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132200210103323 - 210 = 132200210102299 is a prime.
It is not a weakly prime, because it can be changed into another prime (132200210103823) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66100105051661 + 66100105051662.
It is an arithmetic number, because the mean of its divisors is an integer number (66100105051662).
Almost surely, 2132200210103323 is an apocalyptic number.
132200210103323 is a deficient number, since it is larger than the sum of its proper divisors (1).
132200210103323 is an equidigital number, since it uses as much as digits as its factorization.
132200210103323 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 132200210103323 its reverse (323301012002231), we get a palindrome (455501222105554).
The spelling of 132200210103323 in words is "one hundred thirty-two trillion, two hundred billion, two hundred ten million, one hundred three thousand, three hundred twenty-three".
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