Base | Representation |
---|---|
bin | 111101100011111001… |
… | …0110111101011101001 |
3 | 110122020022112122122011 |
4 | 1323013302313223221 |
5 | 4131221430121022 |
6 | 140422102355521 |
7 | 12360031062454 |
oct | 1730762675351 |
9 | 418208478564 |
10 | 132201020137 |
11 | 5108003613a |
12 | 21755a2bba1 |
13 | c60aba2604 |
14 | 658193049b |
15 | 368b1d2977 |
hex | 1ec7cb7ae9 |
132201020137 has 2 divisors, whose sum is σ = 132201020138. Its totient is φ = 132201020136.
The previous prime is 132201020131. The next prime is 132201020173. The reversal of 132201020137 is 731020102231.
It is a happy number.
Together with next prime (132201020173) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 124154750736 + 8046269401 = 352356^2 + 89701^2 .
It is a cyclic number.
It is not a de Polignac number, because 132201020137 - 27 = 132201020009 is a prime.
It is not a weakly prime, because it can be changed into another prime (132201020131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66100510068 + 66100510069.
It is an arithmetic number, because the mean of its divisors is an integer number (66100510069).
Almost surely, 2132201020137 is an apocalyptic number.
It is an amenable number.
132201020137 is a deficient number, since it is larger than the sum of its proper divisors (1).
132201020137 is an equidigital number, since it uses as much as digits as its factorization.
132201020137 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 504, while the sum is 22.
Adding to 132201020137 its reverse (731020102231), we get a palindrome (863221122368).
The spelling of 132201020137 in words is "one hundred thirty-two billion, two hundred one million, twenty thousand, one hundred thirty-seven".
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