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13220113433 = 26381161981
BaseRepresentation
bin11000100111111101…
…01110110000011001
31021010022222100022212
430103332232300121
5204033322112213
610023452524505
7645415052522
oct142376566031
937108870285
1013220113433
11567445598a
12268b480735
131328b7bc37
148d5aa5849
155259309a8
hex313faec19

13220113433 has 8 divisors (see below), whose sum is σ = 13286957376. Its totient is φ = 13153395600.

The previous prime is 13220113429. The next prime is 13220113453. The reversal of 13220113433 is 33431102231.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13220113433 - 22 = 13220113429 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 13220113399 and 13220113408.

It is not an unprimeable number, because it can be changed into a prime (13220113453) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 182303 + ... + 244283.

It is an arithmetic number, because the mean of its divisors is an integer number (1660869672).

Almost surely, 213220113433 is an apocalyptic number.

It is an amenable number.

13220113433 is a deficient number, since it is larger than the sum of its proper divisors (66843943).

13220113433 is an equidigital number, since it uses as much as digits as its factorization.

13220113433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 63055.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 13220113433 its reverse (33431102231), we get a palindrome (46651215664).

The spelling of 13220113433 in words is "thirteen billion, two hundred twenty million, one hundred thirteen thousand, four hundred thirty-three".

Divisors: 1 263 811 61981 213293 16301003 50266591 13220113433