Base | Representation |
---|---|
bin | 11110000011110001111101… |
… | …101101000000111110101101 |
3 | 122100002022102002112011211121 |
4 | 132003301331231000332231 |
5 | 114311441030243321443 |
6 | 1145100221031020541 |
7 | 36563136014556511 |
oct | 3603617555007655 |
9 | 570068362464747 |
10 | 132201202323373 |
11 | 3913a240262597 |
12 | 129b158b20a751 |
13 | 589c69b264571 |
14 | 24908026a6141 |
15 | 1043ccb3444ed |
hex | 783c7db40fad |
132201202323373 has 2 divisors, whose sum is σ = 132201202323374. Its totient is φ = 132201202323372.
The previous prime is 132201202323343. The next prime is 132201202323391. The reversal of 132201202323373 is 373323202102231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 124767961721764 + 7433240601609 = 11169958^2 + 2726397^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132201202323373 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132201202323343) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66100601161686 + 66100601161687.
It is an arithmetic number, because the mean of its divisors is an integer number (66100601161687).
Almost surely, 2132201202323373 is an apocalyptic number.
It is an amenable number.
132201202323373 is a deficient number, since it is larger than the sum of its proper divisors (1).
132201202323373 is an equidigital number, since it uses as much as digits as its factorization.
132201202323373 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54432, while the sum is 34.
The spelling of 132201202323373 in words is "one hundred thirty-two trillion, two hundred one billion, two hundred two million, three hundred twenty-three thousand, three hundred seventy-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.080 sec. • engine limits •