Base | Representation |
---|---|
bin | 1100000001100000110100… |
… | …1101100101011111000011 |
3 | 1201210211110122211002101221 |
4 | 3000120031031211133003 |
5 | 3213044312014033212 |
6 | 44041124435535511 |
7 | 2533060112266255 |
oct | 300301515453703 |
9 | 51724418732357 |
10 | 13220131002307 |
11 | 4237698336989 |
12 | 159619715a597 |
13 | 74b86485bc78 |
14 | 339c0196dcd5 |
15 | 17dd45102807 |
hex | c060d3657c3 |
13220131002307 has 2 divisors, whose sum is σ = 13220131002308. Its totient is φ = 13220131002306.
The previous prime is 13220131002251. The next prime is 13220131002313. The reversal of 13220131002307 is 70320013102231.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13220131002307 - 223 = 13220122613699 is a prime.
It is not a weakly prime, because it can be changed into another prime (13220131002347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6610065501153 + 6610065501154.
It is an arithmetic number, because the mean of its divisors is an integer number (6610065501154).
Almost surely, 213220131002307 is an apocalyptic number.
13220131002307 is a deficient number, since it is larger than the sum of its proper divisors (1).
13220131002307 is an equidigital number, since it uses as much as digits as its factorization.
13220131002307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1512, while the sum is 25.
Adding to 13220131002307 its reverse (70320013102231), we get a palindrome (83540144104538).
The spelling of 13220131002307 in words is "thirteen trillion, two hundred twenty billion, one hundred thirty-one million, two thousand, three hundred seven".
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