Base | Representation |
---|---|
bin | 11110000011110010101101… |
… | …011011011001011001001111 |
3 | 122100002101110220011022222111 |
4 | 132003302231123121121033 |
5 | 114311444200232324101 |
6 | 1145100432312324451 |
7 | 36563164606366303 |
oct | 3603625533313117 |
9 | 570071426138874 |
10 | 132202003011151 |
11 | 3913a611223127 |
12 | 129b17733a3727 |
13 | 589c7980c8508 |
14 | 249087ab6dd03 |
15 | 1043d267a5251 |
hex | 783cad6d964f |
132202003011151 has 2 divisors, whose sum is σ = 132202003011152. Its totient is φ = 132202003011150.
The previous prime is 132202003011109. The next prime is 132202003011167. The reversal of 132202003011151 is 151110300202231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132202003011151 - 243 = 123405909988943 is a prime.
It is a super-3 number, since 3×1322020030111513 (a number of 43 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132202003911151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66101001505575 + 66101001505576.
It is an arithmetic number, because the mean of its divisors is an integer number (66101001505576).
Almost surely, 2132202003011151 is an apocalyptic number.
132202003011151 is a deficient number, since it is larger than the sum of its proper divisors (1).
132202003011151 is an equidigital number, since it uses as much as digits as its factorization.
132202003011151 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 360, while the sum is 22.
Adding to 132202003011151 its reverse (151110300202231), we get a palindrome (283312303213382).
The spelling of 132202003011151 in words is "one hundred thirty-two trillion, two hundred two billion, three million, eleven thousand, one hundred fifty-one".
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