13220202044041 has 2 divisors, whose sum is σ = 13220202044042. Its totient is φ = 13220202044040.

The previous prime is 13220202044011. The next prime is 13220202044051. The reversal of 13220202044041 is 14044020202231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11007929552400 + 2212272491641 = 3317820^2 + 1487371^2 .

It is a cyclic number.

It is not a de Polignac number, because 13220202044041 - 2¹⁵ = 13220202011273 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13220202043997 and 13220202044015.

It is not a weakly prime, because it can be changed into another prime (13220202044011) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6610101022020 + 6610101022021.

It is an arithmetic number, because the mean of its divisors is an integer number (6610101022021).

Almost surely, 2^{13220202044041} is an apocalyptic number.

It is an amenable number.

13220202044041 is a deficient number, since it is larger than the sum of its proper divisors (1).

13220202044041 is an equidigital number, since it uses as much as digits as its factorization.

13220202044041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3072, while the sum is 25.

Adding to 13220202044041 its reverse (14044020202231), we get a palindrome (27264222246272).

The spelling of 13220202044041 in words is "thirteen trillion, two hundred twenty billion, two hundred two million, forty-four thousand, forty-one".