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132203121000000 = 26356192319353
BaseRepresentation
bin11110000011110011110000…
…000100001011111001000000
3122100002111100210212001100220
4132003303300010023321000
5114312003442434000000
61145101135250543040
736563234403214101
oct3603636004137100
9570074323761326
10132203121000000
1139140035304756
12129b1a25897a80
13589c91590708b
1424909454323a8
151043d8e9e11a0
hex783cf010be40

132203121000000 has 392 divisors, whose sum is σ = 460240918215840. Its totient is φ = 33398668800000.

The previous prime is 132203120999987. The next prime is 132203121000031. The reversal of 132203121000000 is 121302231.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is an unprimeable number.

It is a polite number, since it can be written in 55 ways as a sum of consecutive naturals, for example, 55840324 + ... + 58159676.

Almost surely, 2132203121000000 is an apocalyptic number.

132203121000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 132203121000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (230120459107920).

132203121000000 is an abundant number, since it is smaller than the sum of its proper divisors (328037797215840).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

132203121000000 is an frugal number, since it uses more digits than its factorization.

132203121000000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2319417 (or 2319382 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 132203121000000 its reverse (121302231), we get a palindrome (132203242302231).

The spelling of 132203121000000 in words is "one hundred thirty-two trillion, two hundred three billion, one hundred twenty-one million", and thus it is an aban number.