Base | Representation |
---|---|
bin | 11110000011110011110101… |
… | …100011111001101101001111 |
3 | 122100002111121020100022021101 |
4 | 132003303311203321231033 |
5 | 114312004140034401312 |
6 | 1145101152343043531 |
7 | 36563236603002262 |
oct | 3603636543715517 |
9 | 570074536308241 |
10 | 132203213200207 |
11 | 39140082359076 |
12 | 129b1a507405a7 |
13 | 589c92ba49606 |
14 | 2490953792cd9 |
15 | 1043d97b54a57 |
hex | 783cf58f9b4f |
132203213200207 has 2 divisors, whose sum is σ = 132203213200208. Its totient is φ = 132203213200206.
The previous prime is 132203213200193. The next prime is 132203213200211. The reversal of 132203213200207 is 702002312302231.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132203213200207 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132203213200507) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66101606600103 + 66101606600104.
It is an arithmetic number, because the mean of its divisors is an integer number (66101606600104).
Almost surely, 2132203213200207 is an apocalyptic number.
132203213200207 is a deficient number, since it is larger than the sum of its proper divisors (1).
132203213200207 is an equidigital number, since it uses as much as digits as its factorization.
132203213200207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6048, while the sum is 28.
Adding to 132203213200207 its reverse (702002312302231), we get a palindrome (834205525502438).
The spelling of 132203213200207 in words is "one hundred thirty-two trillion, two hundred three billion, two hundred thirteen million, two hundred thousand, two hundred seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •