13220433001433 has 4 divisors (see below), whose sum is σ = 15109066287360. Its totient is φ = 11331799715508.

The previous prime is 13220433001429. The next prime is 13220433001463. The reversal of 13220433001433 is 33410033402231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13220433001433 - 2² = 13220433001429 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13220433001396 and 13220433001405.

It is not an unprimeable number, because it can be changed into a prime (13220433001463) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 944316642953 + ... + 944316642966.

It is an arithmetic number, because the mean of its divisors is an integer number (3777266571840).

Almost surely, 2^{13220433001433} is an apocalyptic number.

It is an amenable number.

13220433001433 is a deficient number, since it is larger than the sum of its proper divisors (1888633285927).

13220433001433 is an equidigital number, since it uses as much as digits as its factorization.

13220433001433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1888633285926.

The product of its (nonzero) digits is 15552, while the sum is 29.

Adding to 13220433001433 its reverse (33410033402231), we get a palindrome (46630466403664).

The spelling of 13220433001433 in words is "thirteen trillion, two hundred twenty billion, four hundred thirty-three million, one thousand, four hundred thirty-three".