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13220433001429 is a prime number
BaseRepresentation
bin1100000001100001111100…
…1101100111101111010101
31201210212020201002020022121
43000120133031213233111
53213100421322021204
644041214424455541
72533100440243213
oct300303715475725
951725221066277
1013220433001429
114237832856335
12159626031a5b1
1374b8b22a9984
14339c2db03cb3
1517dd618a8b54
hexc061f367bd5

13220433001429 has 2 divisors, whose sum is σ = 13220433001430. Its totient is φ = 13220433001428.

The previous prime is 13220433001409. The next prime is 13220433001463. The reversal of 13220433001429 is 92410033402231.

It is an a-pointer prime, because the next prime (13220433001463) can be obtained adding 13220433001429 to its sum of digits (34).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13218299947204 + 2133054225 = 3635698^2 + 46185^2 .

It is a cyclic number.

It is not a de Polignac number, because 13220433001429 - 27 = 13220433001301 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13220433001394 and 13220433001403.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13220433001409) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6610216500714 + 6610216500715.

It is an arithmetic number, because the mean of its divisors is an integer number (6610216500715).

Almost surely, 213220433001429 is an apocalyptic number.

It is an amenable number.

13220433001429 is a deficient number, since it is larger than the sum of its proper divisors (1).

13220433001429 is an equidigital number, since it uses as much as digits as its factorization.

13220433001429 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 31104, while the sum is 34.

The spelling of 13220433001429 in words is "thirteen trillion, two hundred twenty billion, four hundred thirty-three million, one thousand, four hundred twenty-nine".