Base | Representation |
---|---|
bin | 11110000011111010011101… |
… | …111100001101101100001100 |
3 | 122100010011222102201100121220 |
4 | 132003322131330031230030 |
5 | 114312113230234104400 |
6 | 1145104331043323340 |
7 | 36563611206160644 |
oct | 3603723574155414 |
9 | 570104872640556 |
10 | 132210333113100 |
11 | 391430a6365000 |
12 | 129b32b9080550 |
13 | 58a04c4b48918 |
14 | 249102b205524 |
15 | 1044162c587a0 |
hex | 783e9df0db0c |
132210333113100 has 2304 divisors, whose sum is σ = 478056902400000. Its totient is φ = 28073325772800.
The previous prime is 132210333113041. The next prime is 132210333113107. The reversal of 132210333113100 is 1311333012231.
132210333113100 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a super-2 number, since 2×1322103331131002 (a number of 29 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (132210333113107) by changing a digit.
It is a polite number, since it can be written in 767 ways as a sum of consecutive naturals, for example, 887317671826 + ... + 887317671974.
It is an arithmetic number, because the mean of its divisors is an integer number (207489975000).
Almost surely, 2132210333113100 is an apocalyptic number.
132210333113100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 132210333113100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (239028451200000).
132210333113100 is an abundant number, since it is smaller than the sum of its proper divisors (345846569286900).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
132210333113100 is a wasteful number, since it uses less digits than its factorization.
132210333113100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 393 (or 364 counting only the distinct ones).
The product of its (nonzero) digits is 972, while the sum is 24.
Adding to 132210333113100 its reverse (1311333012231), we get a palindrome (133521666125331).
The spelling of 132210333113100 in words is "one hundred thirty-two trillion, two hundred ten billion, three hundred thirty-three million, one hundred thirteen thousand, one hundred".
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