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132212113102 = 266106056551
BaseRepresentation
bin111101100100001110…
…1001011111011001110
3110122021002102020022201
41323020131023323032
54131232300104402
6140423140232114
712360224263456
oct1731035137316
9418232366281
10132212113102
1151086322483
122175969b63a
13c6102877b4
1465831bad66
15368c174687
hex1ec874bece

132212113102 has 4 divisors (see below), whose sum is σ = 198318169656. Its totient is φ = 66106056550.

The previous prime is 132212113087. The next prime is 132212113109. The reversal of 132212113102 is 201311212231.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 201311212231 = 296941765939.

It is a self number, because there is not a number n which added to its sum of digits gives 132212113102.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132212113109) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33053028274 + ... + 33053028277.

It is an arithmetic number, because the mean of its divisors is an integer number (49579542414).

Almost surely, 2132212113102 is an apocalyptic number.

132212113102 is a deficient number, since it is larger than the sum of its proper divisors (66106056554).

132212113102 is an equidigital number, since it uses as much as digits as its factorization.

132212113102 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 66106056553.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 132212113102 its reverse (201311212231), we get a palindrome (333523325333).

The spelling of 132212113102 in words is "one hundred thirty-two billion, two hundred twelve million, one hundred thirteen thousand, one hundred two".

Divisors: 1 2 66106056551 132212113102